If a sewage spill runs at 6 gallons per minute and the stoppage is relieved 27 minutes after the call, how much sewage went uncaptured?

To determine the amount of sewage that went uncaptured, you need to calculate the total volume of sewage spilled over the 27 minutes before the stoppage was relieved. The rate of the spill is given as 6 gallons per minute.

To find the total volume, multiply the flow rate (6 gallons per minute) by the total time of the spill (27 minutes):

Total sewage spilled = Flow rate × Time Total sewage spilled = 6 gallons/minute × 27 minutes Total sewage spilled = 162 gallons

This calculation shows that the correct answer is 162 gallons, indicating the total amount of sewage that went uncaptured before the situation was addressed. Understanding the relationship between flow rate and time is crucial in assessing the impact of spills in collection systems.